How many distinct arrangements of the letters in the word football are possible. Therefore, there are 6! such arrangements.
How many distinct arrangements of the letters in the word football are possible. a) How many different arrangements are there of the letters of the word numbers? 7! = 5,040 b) How many of those arrangements have b as the first letter? Set b as the first letter, and permute the remaining 6. To account for the repeated letters, we divide by the factorial of the number of The first space can be filled by any one of the four letters. 8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 40320. Approach to solving the problem: Identify the number of letters in the word "football" and the number of times each letter is repeated. We have an expert-written solution to this problem! There are 77 performers who are to present their acts at a variety show. 6!. Therefore, there are 6! such arrangements. The third space can be filled by any of the 2 remaining letters and the final space must be filled by the one remaining letter. To find the number of distinct arrangements, we calculate 8! and then divide by 2! (the number of ways to arrange the two Os). If all the letters were distinct, there would be 8! arrangements. k6b s52m4i fqn kim 88k6j5bg 57 7gyv 9s7zn0 pwuuip p0nc
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